F(x)=3x^+18x+32

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Solution for F(x)=3x^+18x+32 equation: 



(F)=3F^+18F+32

We move all terms to the left:

(F)-(3F^+18F+32)=0

We get rid of parentheses

F-3F^-18F-32=0

We add all the numbers together, and all the variables

-20F-32=0

We move all terms containing F to the left, all other terms to the right

-20F=32

F=32/-20

F=-1+3/5

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